SOLUTION: Let (theta) be an angle in quadrant II such that sin(theta)= 4/5. Find the exact values of sec(theta) and cot(theta).

Click here to see ALL problems on Trigonometry-basics

Question 951136: Let (theta) be an angle in quadrant II such that sin(theta)= 4/5. Find the exact values of sec(theta) and cot(theta).

Found 2 solutions by lwsshak3, Alan3354:
Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website!
Let (theta) be an angle in quadrant II such that sin(theta)= 4/5. Find the exact values of sec(theta) and cot(theta).
***
working with a (3-4-5) reference right triangle in quadrant II where sin>0, cos<0
cos(theta)=-3/5
sec(theta)=1/cos(theta)=-5/3
cot(theta)=cos/sin=-3/4

Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website!
Very similar to this one:
===================
If tan theta=3/2 and cos theta<0, find the other five trig functions of theta
----------
tan = y/x = 3/2
r = sqrt(y^2 + x^2) = sqrt(13)
-----
tan + and cos < 0 --> Q3
---
sin = y/r = 3/sqrt(13) --> -3sqrt(13)/13
cos = x/r = 2sqrt(13)/13
cot = 1/tan
sec = 1/cos
csc = 1/sin