SOLUTION: 2-2Cos^2(x)-√2sinx=0 need help asap? I got radical2/2 but i dont think thats right. Please help

Algebra ->  Trigonometry-basics -> SOLUTION: 2-2Cos^2(x)-√2sinx=0 need help asap? I got radical2/2 but i dont think thats right. Please help      Log On


   

Question 951033: 2-2Cos^2(x)-√2sinx=0 need help asap?
I got radical2/2 but i dont think thats right. Please help
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
2+-+2%2Acos%5E2%28x%29+-+sqrt%282%29%2Asin%28x%29+=+0
cos%5E2%28x%29+=+1+-+sin%5E2%28x%29
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2+-+2%2A%281+-+sin%5E2%28x%29%29+-+sqrt%282%29%2Asin%28x%29+=+0
2+-+2+%2B+2sin%5E2%28x%29+-+sqrt%282%29%2Asin%28x%29+=+0
2sin%5E2%28x%29+-+sqrt%282%29%2Asin%28x%29+=+0
sin%28x%29%2A%282sin%28x%29+-+sqrt%282%29%29+=+0
sin(x) = 0
x = 0, pi, 2pi, etc
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2sin(x) - sqrt(2) = 0
sin(x) = sqrt(2)/2
x = pi/4, 3pi/4, etc