SOLUTION: So how would I solve the equation: log2x+logx=11 for x? I'm stuck on this one, thanks!

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: So how would I solve the equation: log2x+logx=11 for x? I'm stuck on this one, thanks!      Log On


   

Question 950860: So how would I solve the equation: log2x+logx=11 for x?
I'm stuck on this one, thanks!
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
So how would I solve the equation:
log2x+logx=11 for x?
log(2x*x)=11
log(2x^2)=11
10^11=2x^2
x^2=(10^11)/2
x=±sqrt%2810%5E10%2A10%29%2F2=±(10^5√10)/2