SOLUTION: A field is in the shape of a rectangle.The ratio
of the length of the field to its width is 3 to 2. If the
perimeter of the field is 190 yards, what is the demensions
of the f
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-> SOLUTION: A field is in the shape of a rectangle.The ratio
of the length of the field to its width is 3 to 2. If the
perimeter of the field is 190 yards, what is the demensions
of the f
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Question 95085: A field is in the shape of a rectangle.The ratio
of the length of the field to its width is 3 to 2. If the
perimeter of the field is 190 yards, what is the demensions
of the field? Answer by checkley71(8403) (Show Source):
You can put this solution on YOUR website! 3*2X+2*2X=190
6X+4X=190
10X=190
X=190/10
X=19
3*19=57 LENGTH.
2*19=38 WIDTH.
PROOF
2*57+2*38=190
114+76=190
190=190
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