Question 95072: 8/(2a - 2b) - 3b/(a^2-B^2)
PLEASE HELP ME, NEED TUTORING ON THIS, PLEASE STEP BY STEP, ON A TEST TOMORROW, VERY CONFUSED?? Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 8/(2a - 2b) - 3b/(a^2-B^2)
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[8/(2(a-b))] - [3b/(a-b)(a+b)]
[4/(a-b)] -[3b/(a-b)(a+b)]
Least common denominator is (a+b)(a-b)
Rewrite each fraction with the lcd as its denominator:
[4(a+b)/lcd] - [3b/lcd]
Since the denominators are now the same combine the numerators over the lcd
[4-3b]/lcd
= [4-3b]/[(a+b)(a-b)]
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Cheers,
Stan H.
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