Question 950667: sir please this is my last question help me to solve.
Yeboah is 37 times as old as Aseidu.
in 16years time yeboah would be twice as old as Aseidu.
find their ages.
Thank you
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website! yeboah is 37 times as old as asseidu.
let a = age of yeboah.
let b = age of asseidu.
equation becomes a = 37 * b
in 16 years yeboah will be twice as old as asseidu.
equation becomes (a + 16) = 2 * (b + 16)
find their ages.
you have two equations that need to be solved simultaneously.
they are:
a = 37 * b
(a + 16) = 2 * (b + 16)
replace a in the second equation with 37 * b.
your second equation of (a + 16) = 2 * (b + 16) becomes:
(37 * b + 16) = 2 * (b + 16)
simplify to get
37 * b + 16 = 2 * b + 32
subtract 16 from both sides of the equation and subtract 2 * b from both sides of the equation to get:
37 * b - 2 * b = 32 - 16
simplify to get:
35 * b = 16
divide both sides of the equation by 34 to get:
b = 16 / 35 = .4571428571
since a = 37 * b, then a = 16.91428571
in 16 years, a will be equal to 16.91428571 + 16 = 32.91428571
in 16 years, b will be equal to .4571428571 + 16 = 16.4571428571.
in 16 years a will be 2 * b.
this becomes 32.91428571 = 2 * 16.4571428571.
2 * 16.4571428571 is equal to 32.91428571.
this confirms the solution is correct.
assuming the problem was stated correctly.
yeboah is 16.91428571 years old today.
asseidu is .4571428571 years old today.
16.91428571 / .4571428571 = 37
yeboah is 37 times as old as asseidu today.
yeboah is 32.91428571 years old in 16 years.
asseidu is 16.45714286 years old in 16 years.
32.91428571 / 16.45714286 = 2
yeboah is 2 times as old as asseidu in 16 years.
strange numbers, but that's the way it comes out, assuming the original problem is stated as given.
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