SOLUTION: find three consecutive even integers such that the product of the first and the third integers equals 4 less than 8 times the second integer
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Question 950653
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find three consecutive even integers such that the product of the first and the third integers equals 4 less than 8 times the second integer
Answer by
CubeyThePenguin(3113)
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consecutive even integers: (x-2), x, (x+2)
(x-2)(x+2) = 8x - 4
x^2 - 4 = 8x - 4
x^2 - 8x = 0
x(x - 8) = 0
The integers could be {-2, 0, 2} or {6, 8, 10.}