SOLUTION: A lot of 1000 components contains 250 that are defective. Two components are drawn at random and tested. Let A be the event that the first component drawn is defective, and let B b

Algebra ->  Probability-and-statistics -> SOLUTION: A lot of 1000 components contains 250 that are defective. Two components are drawn at random and tested. Let A be the event that the first component drawn is defective, and let B b      Log On


   

Question 950575: A lot of 1000 components contains 250 that are defective. Two components are drawn at random and tested. Let A be the event that the first component drawn is defective, and let B be the event that the second component drawn is defective.
find P(B|A)
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
P(B|A)=P(A_and_B)/P(A)
However since A and B are independent,
P%28A_and_B%29=P%28A%29%2AP%28B%29
so
P%28A_and_B%29%2FP%28A%29=P%28B%29
and
P(B|A)=P%28B%29=249%2F999