SOLUTION: Find three consecutive positive odd intergers such that the sum of the squares of the first two integers is 15 less than the square of the third

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Question 950544: Find three consecutive positive odd intergers such that the sum of the squares of the first two integers is 15 less than the square of the third
Answer by jhaashok630(18) About Me  (Show Source):
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three consecutive positive odd intergers such that the sum of the squares of the first two integers is 15 less than the square of the third
let x= first odd integer
2nd integer = x+2
3rd integer = x+4
x^2+(x+2)^2=(x+4)^2-15
x=1 , 3 , 5