SOLUTION: Kathryn and Tiana both leave the study group at the same time, but in opposite directions. If Tiana travels 9 mph faster than Kathryn and after 3 hours they are 117 miles apart, ho

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Question 950470: Kathryn and Tiana both leave the study group at the same time, but in opposite directions. If Tiana travels 9 mph faster than Kathryn and after 3 hours they are 117 miles apart, how fast is each traveling?
Kathryn is traveling_mph?
Tiana is traveling_mph?
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
Kathryn and Tiana both leave the study group at the same time, but in opposite directions. If Tiana travels 9 mph faster than Kathryn and after 3 hours they are 117 miles apart, how fast is each traveling?
K=Kathryn's rate; T=Tiana's rate=K+9mph;
117/3 hrs==39 mi/hr Their combined rate is 39 mph.
K+T=39mph Substitute for T.
K+K+9mph=39mph Subtract 9 mph from each side.
2K=30mph Divide each side by 2.
K=15 mph ANSWER 1: Kathryn's speed was 15 mph.
T=K+9mph=24 mph ANSWER 2:Tiana's speed was 24 mph.