SOLUTION: (3x-5)/(x) >0
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Hint: Either both the numerator and the denominator are positive, or both are negative; consider both cases.
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My attempt:
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(3x-5)/(x) >0
(x)/(1) (3x-5)/(x)
Algebra ->
Inequalities
-> SOLUTION: (3x-5)/(x) >0
.
Hint: Either both the numerator and the denominator are positive, or both are negative; consider both cases.
.
My attempt:
.
(3x-5)/(x) >0
(x)/(1) (3x-5)/(x)
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Question 950319: (3x-5)/(x) >0
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Hint: Either both the numerator and the denominator are positive, or both are negative; consider both cases.
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My attempt:
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(3x-5)/(x) >0
(x)/(1) (3x-5)/(x)=0(x)
3x-5=0
3x=5
3x/3=5/3
x=5/3
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x>5/3
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interval notation
-2<-----0 5/3------5
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Can someone check this for me? Thanks in advance. Answer by Fombitz(32388) (Show Source):
You can put this solution on YOUR website! OK, I'm not sure about your interval notation.
The first part of the answer is correct.
In interval notation that would be (,).
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You also have to consider the case where both numerator and denominator are negative.
Then,
Both conditions have the hold simultaneously so, putting those together gives you
So the final answer in interval notation would be,
(,)U(,)
