SOLUTION: How to find degree of polynomial. P(x) = x^3(x+2)(x-3)^2 I know the points on the x-axis are 0,-2,+3 the trouble I am having is determining it's degree. I know x^3 is the highe

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: How to find degree of polynomial. P(x) = x^3(x+2)(x-3)^2 I know the points on the x-axis are 0,-2,+3 the trouble I am having is determining it's degree. I know x^3 is the highe      Log On


   

Question 950210: How to find degree of polynomial.
P(x) = x^3(x+2)(x-3)^2
I know the points on the x-axis are 0,-2,+3 the trouble I am having is determining it's degree. I know x^3 is the highest here? so then it would be an odd positive graph? from the bottom left to the top right? but when I graph it online it gives me the graph an odd negative graph. What did I miss?
Thanks!
Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
This is a 6th degree polynomial and you should get this graph



this grapher isn't perfect as the green line should extend upwards infinitely on the left side

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
How to find degree of polynomial.
P(x) = x^3(x+2)(x-3)^2
I know the points on the x-axis are 0,-2,+3 the trouble I am having is determining it's degree. I know x^3 is the highest here? so then it would be an odd positive graph? from the bottom left to the top right? but when I graph it online it gives me the graph an odd negative graph. What did I miss?
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The degree is 6;; 3+1+2 = 6.
graph%28400%2C400%2C-10%2C10%2C-10%2C10%2Cx%5E3%2A%28x%2B2%29%28x-3%29%5E2%29
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Cheers,
Stan H.
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