SOLUTION: Please explain how to get the y-intercept(s) 1/2(x-1)^3 + 4 = 0 Thank you

Algebra ->  Graphs -> SOLUTION: Please explain how to get the y-intercept(s) 1/2(x-1)^3 + 4 = 0 Thank you      Log On


   

Question 950098: Please explain how to get the y-intercept(s) 1/2(x-1)^3 + 4 = 0
Thank you
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The y-intercept is located where
+x+=+0+
+%281%2F2%29%2A%28+x-1+%29%5E3+%2B+4+=+0+
This is the equation to locate the
roots by setting +y+=+0+, so I
will change it to:
+y+=+%281%2F2%29%2A%28+x-1+%29%5E3+%2B+4+
+y+=+%281%2F2%29%2A%28+0-1+%29%5E3+%2B+4+
+y+=+%281%2F2%29%2A%28-1%29+%2B+4+
+y+=+-1%2F2+%2B+4+
+y+=+-1%2F2+%2B+8%2F2+
++y+=+7%2F2+
---------------
The y-intercept is at ( 0, 7/2 )
Here's the plot:
+graph%28+400%2C+400%2C+-7%2C+7%2C+-7%2C+7%2C+%281%2F2%29%2A%28+x-1+%29%5E3+%2B+4+%29+