SOLUTION: Given vertices (2,-1) and (-16,-1) and endpoints of conjugate axis, (-7,5) and (-7,-7) what is the hyperbolas equation ?

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Question 950024: Given vertices (2,-1) and (-16,-1) and endpoints of conjugate axis, (-7,5) and (-7,-7) what is the hyperbolas equation ?
Answer by lwsshak3(11628) About Me  (Show Source):
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Given vertices (2,-1) and (-16,-1) and endpoints of conjugate axis, (-7,5) and (-7,-7) what is the hyperbolas equation ?
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hyperbola has a horizontal transverse axis.
Its standard form of equation: %28x-h%29%5E2%2Fa%5E2-%28y-k%29%5E2%2Fb%5E2=1, (h,k)=coordinates of center
center: (-7,-1)
length of horizontal transverse axis=18=2a
a=9
a^2=81
length of conjugate axis=12=2b
b=6
b^2=36
equation: %28x%2B7%29%5E2%2F81-%28y%2B1%29%5E2%2F36=1