SOLUTION: Find all values of t in the interval [0, 2&#960;] satisfying the given equation. (Enter your answers as a comma-separated list.) (4 cot t)^2 = 48

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Question 949907: Find all values of t in the interval [0, 2π] satisfying the given equation. (Enter your answers as a comma-separated list.)
(4 cot t)^2 = 48

Found 2 solutions by lwsshak3, ikleyn:
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website!
Find all values of t in the interval [0, 2π] satisfying the given equation. (Enter your answers as a comma-separated list.)
(4 cot t)^2 = 48
take sqrt of both sides
4cot t=�√48=4�√3
cot t=(4�√3)/4
..
cot t=(4+√3)/4
t≈1.04, 4.18 (radians) (In quadrants I and III where cot>0)
..
cot t=(4-√3)/4
t≈1.94, 4.34 (radians) (In quadrants II and IV where cot<0)

Answer by ikleyn(53937)   (Show Source):
You can put this solution on YOUR website!
.
Find all values of t in the interval [0, 2π] satisfying the given equation.
(Enter your answers as a comma-separated list.)
(4 cot t)^2 = 48
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

        The solution in the post by @lwsshar3 is INCORRECT.
        Below is my correct solution.

(4*cos(t))^2 = 48 16cot(t)^2 = 48 cot(t)^2 = 48/16 = 3 cot(t) = +/- t = , , , . ANSWER

Solved correctly.

SOLUTION: Find all values of t in the interval [0, 2&#960;] satisfying the given equation. (Enter your answers as a comma-separated list.) (4 cot t)^2 = 48

SOLUTION: Find all values of t in the interval [0, 2π] satisfying the given equation. (Enter your answers as a comma-separated list.) (4 cot t)^2 = 48