SOLUTION: Find range to function: S(t) = ^4√(t^2+16) in interval form. That is a fourth root in the squareroot symbol. Thanks!

Algebra ->  Functions -> SOLUTION: Find range to function: S(t) = ^4√(t^2+16) in interval form. That is a fourth root in the squareroot symbol. Thanks!      Log On


   

Question 949891: Find range to function: S(t) = ^4√(t^2+16) in interval form. That is a fourth root in the squareroot symbol.
Thanks!
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Find range to function: S(t) = ^4√(t^2+16) in interval form. That is a fourth root in the square root symbol.
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rewrite equation:y=%28t%5E2%2B16%29%5E%281%2F4%29
interchange y and t and solve for y
t=%28y%5E2%2B16%29%5E%281%2F4%29
t%5E4=%28y%5E2%2B16%29
y^2=t^4-16
y=±√t^4-16)
t^4-16≥0
t^4≥16
t≥2
Range of function: [2,∞)