SOLUTION: For a parabola how to find the points on the graph of: f(x)=-3x^2+18x+5
I know I would complete the square to get f(x) = -3(x-3)+32 and from this I would have my vertex: +3,32 so
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-> SOLUTION: For a parabola how to find the points on the graph of: f(x)=-3x^2+18x+5
I know I would complete the square to get f(x) = -3(x-3)+32 and from this I would have my vertex: +3,32 so
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Question 949788: For a parabola how to find the points on the graph of: f(x)=-3x^2+18x+5
I know I would complete the square to get f(x) = -3(x-3)+32 and from this I would have my vertex: +3,32 so I would shoot left 3 and up 32 and have that point I know the graph turn downwards. and to find the y-int I plug in x=0 and get (0,5) but what about the two points this parabola hits on the x-axis how do I find those points?
Thank you Answer by macston(5194) (Show Source):