Question 949610: with axis x=-2, length of the latus rectum = 6, and passing through (4,8). find the equation of the parabola whose vertex is at (h,k).
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! with axis x=-2, length of the latus rectum = 6, and passing through (4,8). find the equation of the parabola whose vertex is at (h,k).
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Given parabola opens upward:
Its basic equation: (x-h)^2=4p(y-k)
latus rectum=6=4p
equation:(x-h)^2=6(y-k)
h=-2
using coordinates of given point (4,8)
(4+2)^2=6(8-k)
36=48-6k
6k=12
k=2
equation:(x+2)^2=6(y-2)
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