Question 949541: The length of a rectangle is three times its width. If the perimeter of the rectangle is 64m, find its area Found 2 solutions by macston, addingup:Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! The length of a rectangle is three times its width. If the perimeter of the rectangle is 64m, find its area
W=width; L=length=3W; P=perimeter=2(L+W)
P=2(L+W)
64m=2(L+W) Divide each side by 2.
32 m=L+W Substitute for L.
32 m=3W+W
32m=4W Divide each side by 4.
8m=W The width is 8 meters.
L=3W=3(8 m)=24 m The length is 24 meters.
A=L*W=24 m*8 m=192 sq m ANSWER: The area is 192 square meters.
You can put this solution on YOUR website! The perimeter equals 2 times the length plus 2 times the width:
2L + 2W = Perimeter, which in your problem is 64
And since the length is 3 times the width, we can say that:
L = 3W Now, using this information we re-write the first equation:
3(2W) + 2W = 64 simplify:
6W + 2W = 64 Add on the left:
8W = 64 Now divide both sides by 8:
W= 8
Proof: 3(2*8) + 2*8 = 64; 48 + 16 = 64 We have the correct answer.
