SOLUTION: the length and width of a rectangle are consecutive even integers, The perimeter is 44 meters. Find the length and width.
Hello! I need help with this geometry problem. So far,
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-> SOLUTION: the length and width of a rectangle are consecutive even integers, The perimeter is 44 meters. Find the length and width.
Hello! I need help with this geometry problem. So far,
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Question 949205: the length and width of a rectangle are consecutive even integers, The perimeter is 44 meters. Find the length and width.
Hello! I need help with this geometry problem. So far, I have x+2+x+4+x+6+x+8=44
4x+20=44
24/4=6
I'm not sure if this is the correct way to do this? Please help me. Thanks! Answer by rothauserc(4718) (Show Source):
You can put this solution on YOUR website! let x be first even integer, then x+2 is the second even integer
Perimeter(P) = 44 and 2l + 2w = P, therefore
2x +2(x+2) = 44
2x +2x+4 = 44
4x = 40
x = 10 so we have
10 and 12 as the solution, length=10 and width=12
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check the solution
2*10 + 2*12 = 44
20 +24 = 44
44 = 44
our solution checks
