SOLUTION: Suppose that the playground area has a length of x yards and a width of y yards. The only restriction on the playground is that the area must be 324 square yards. a.In terms of x

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Suppose that the playground area has a length of x yards and a width of y yards. The only restriction on the playground is that the area must be 324 square yards. a.In terms of x       Log On


   



Question 949199: Suppose that the playground area has a length of x yards and a width of y yards. The only restriction on the playground is that the area must be 324 square yards.
a.In terms of x and y, find a formula for the perimeter, P.
b.In terms of x and y, find an equation that models the area of the playground (324 square yards).
c.Combine your formula for the perimeter, P, and the equation of the area by writing a formula for the perimeter, P, in terms of x.
d.Use the formula from Part C to find the Perimeter, P, for each value of x. Include a copy of the completed table in your answer.


x
P


9



10



18


e.Among the three sets of dimensions determined by the values of x above, which set represents the playground area with the smallest perimeter?

Found 2 solutions by rothauserc, MathLover1:
Answer by rothauserc(4718) About Me  (Show Source):
You can put this solution on YOUR website!
a) Perimeter(P) = 2x + 2y
b) 324 = xy
c) from b, y = 324/x, then
P = 2x + 2(324/x)
d) if x = 9, then
P = (2*9) + (2*(324/9))
P = 18 + 72 = 90 yards
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if x = 10, then
P = (2*10) + (2*(324/10))
P = 20 + 64.8 = 84.8 yards
******
if x = 18, then
P = (2*18) + (2*(324/18))
P = 36 + 36 = 72 yards
******
all squares are rectangles but all rectangles are not squares, therefore
72 yards is the minimum perimeter with its sides = 18 yards


Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Suppose that the playground area has a length of L=x yards and a width of W=y+yards. The only restriction on the playground is that the area must be 324 square yards.
the playground area is A=LW
given:
L=x
W=y+
A=324


a.
In terms of x and y, find a formula for the perimeter, P.
since P=2%28L%2BW%29, we have
P=2%28x%2By%29
b.
In terms of x and y, find an equation that models the area of the playground (324 square yards).
since given
L=x
W=y+
A=324
we have xy=324
c.
Combine your formula for the perimeter,+P, and the equation of the area by writing a formula for the perimeter, P, in terms of x.
to do so, first use xy=324yd%5E2 and solve for y
y=324%2Fx....now substitute this in P
P=2%28x%2B324%2Fx%29=>P=2x%2B324%2Fx%29
d.
Use the formula from Part C to find the Perimeter, P, for each value of+x. Include a copy of the completed table in your answer.

x|-----P
9|-----54 ->P=2%2A9%2B324%2F9 ->P=18%2B36 ->P=54
10|----- 52.4 ->P=2%2A10%2B324%2F10 ->P=20%2B32.4 ->P=52.4
18|-----54 ->P=2%2A18%2B324%2F18 ->P=36%2B18%29 ->P=54

e.
Among the three sets of dimensions determined by the values of x+above, which set represents the playground area with the smallest perimeter?
the smallest perimeter P=52.4, so we can find y using
P=2%28x%2By%29
52.4=2%2810%2By%29
52.4%2F2=%2810%2By%29
26.2=10%2By
26.2-10=y
y=16.2
set x=10,y=16.2 represents the playground area with the smallest perimeter