Question 949079: At 3:25 PM two trains left Kalamazoo Michigan. one train traveled west at a constant rate of 82 mph while the other traveled east at a constant rate of 66 mph. if they are now 111 miles apart what time is it now? Write and solve an equation to answer this question. We understand that it is 4:10 PM. We just need to know how to write the equation.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39617)   (Show Source):
Answer by MathTherapy(10552)  (Show Source):
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At 3:25 PM two trains left Kalamazoo Michigan. one train traveled west at a constant rate of 82 mph while the other traveled east at a constant rate of 66 mph. if they are now 111 miles apart what time is it now? Write and solve an equation to answer this question. We understand that it is 4:10 PM. We just need to know how to write the equation.
Let time taken for the trains to be 111 miles apart, be T
Then at that time, the faster train (82 mph) had traveled 82T miles
At that same time, the slower train (66 mph) had traveled 66T miles
When the faster train had covered 82T miles, and the slower train had traveled 66T miles, both had covered 111 miles
Therefore, we can say that: 82T + 66T = 111
148T = 111
T, or time taken by each to cover 111 miles, travelling in opposite directions =  , or  hours, or 
Current time:    , or 
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