SOLUTION: The population of New Haven was 148,220 in 2005. Since then the population has been decreasing at an annual rate of 2.9%. If this rate of decline continues, what will the populat

Algebra ->  Exponents-negative-and-fractional -> SOLUTION: The population of New Haven was 148,220 in 2005. Since then the population has been decreasing at an annual rate of 2.9%. If this rate of decline continues, what will the populat      Log On


   



Question 948907: The population of New Haven was 148,220 in 2005. Since then the population has been decreasing at an annual rate of 2.9%. If this rate of decline continues, what will the population be in the year 2015?

Y = a*bx where a is the starting amount; b is the decay rate (decreasing subtract from 1) ; x is time

Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
a=starting amount; b=decay rate (decreasing subtract from 1)(1-r) ; x is time;
r=rate=2.9%=0.029
x=2015-2005=10 years
This equation should be written:
Y+=+a%2Ab%5Ex
Y=a%281-r%29%5Ex
Y=148220%281-0.029%29%5E10
Y=148220%28.971%29%5E10
Y=148220(.745)=110433 ANSWER: The population at this rate of decline will be 110,433 in 2015.