SOLUTION: Ian and Lindsey are riding bikes in the same direction. Ian is traveling at an average speed of 12 miles per hour and passes a sign at 3:30 pm. Lindsey who is traveling at an avera
Question 948836: Ian and Lindsey are riding bikes in the same direction. Ian is traveling at an average speed of 12 miles per hour and passes a sign at 3:30 pm. Lindsey who is traveling at an average speed of 16 miles per hour, passes the same sign at 3:40 pm. At what time will Lindsey catch up with Ian? Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! Ian and Lindsey are riding bikes in the same direction.
Ian is traveling at an average speed of 12 miles per hour and passes a sign at 3:30 pm.
Lindsey who is traveling at an average speed of 16 miles per hour, passes the same sign at 3:40 pm.
At what time will Lindsey catch up with Ian?
:
From the information given we know that at 3:30 Lindsey is 10 minutes behind Ian
find the distance Lindsey travels in 10 min *(16) = mi Lindsey is behind Ian at 3:30
:
Let t = time required by L to catch I (in hrs)
then
16t = dist traveled by L
12t = dist traveled by I
:
Write a distance equation,
L has to travel 8/3 of a mile more that Ian in the same time,
16t = 12t +
16t - 12t =
4t =
t = *
t = hr; which is *60 = 40 min
:
3:30 + :40 = 4:10 L catches I
