SOLUTION: Find three consecutive integers such that three times the sum of the first and the last is 552. Help would be appreciated, been trying to solve it for about a day.
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Question 948697: Find three consecutive integers such that three times the sum of the first and the last is 552. Help would be appreciated, been trying to solve it for about a day. Answer by macston(5194) (Show Source):
You can put this solution on YOUR website! First integer=X; Last integer=X+2
3(X+(X+2))=552 Divide each side by 3
2X+2=184 Subtract 2 from each side
2X=182 Divide each side by 2
X=91 ANSWER 1: The first integer is 91.
X+2=91+2=93 ANSWER 2: The last integer is 93
CHECK:
Three times the sum is 552
552=3(91+93)
552=3(184)
552=552
The middle integer is X+1=92, not needed in this problem.
