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Question 948696: Find three consecutive integers such that three times the sum of the first and the last is 552. Help would be appreciated, been trying to solve it for about a day.
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Find three consecutive integers
n, (n+1), (n+2)
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such that three times the sum of the first and the last is 552.
3(n + (n+2)) = 552
3(2n + 2) = 552
6n + 6 = 552
6n = 552 - 6
6n = 546
n = 546/6
n = 91 is the 1st integer, then obviously, 92 and 93
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Check this
3(91 + 93) =
3 * 185 = 552
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