SOLUTION: How would I solve for the vertex, directrix and focus coordinates of this parabola? x^2 − 32y = 0 Thanks!

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Question 948688: How would I solve for the vertex, directrix and focus coordinates of this parabola?
x^2 − 32y = 0
Thanks!
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
How would I solve for the vertex, directrix and focus coordinates of this parabola?
x^2 − 32y = 0
x^2=32y
This is an equation of a parabola that opens upward.
Its basic form of equation:(x-h)^2=4p(y-k), (h,k)=coordinates of the vertex
vertex: (0,0)
axis of symmetry: x=0 or y-axis
4p=32
p=8
focus: (0,8) (p-distance above vertex on the axis of symmetry)
directrix: y=-8 (p-distance below vertex on the axis of symmetry)