SOLUTION: hello Solve for x: 2^(2x)-3*2^(x)+2=0. what i did so far was to group them. (2^(2x)-3) * (2^(x)+2). i can say that one of the quantities have to equal zero because the end produ

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: hello Solve for x: 2^(2x)-3*2^(x)+2=0. what i did so far was to group them. (2^(2x)-3) * (2^(x)+2). i can say that one of the quantities have to equal zero because the end produ      Log On


   

Question 948680: hello
Solve for x: 2^(2x)-3*2^(x)+2=0.
what i did so far was to group them. (2^(2x)-3) * (2^(x)+2).
i can say that one of the quantities have to equal zero because the end product is zero. but where do i go from there?
thanks for your help
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
Given 2%5E%282x%29-3%2A2%5E%28x%29%2B2=0

%282%5Ex%29%282%5Ex%29-3%2A2%5Ex%2B2=0

%282%5Ex%29%5E2-3%2A2%5Ex%2B2=0

LET u=2%5Ex and first solve for u. You should find that the quadratic equation in u is factorable.

Continue with u replaced by 2%5Ex in the found roots of u.