SOLUTION: If x squared = 25, y squared = 16, and z squared = 9, what is the greatest possible value of (x+y+z) squared?

Algebra ->  Real-numbers -> SOLUTION: If x squared = 25, y squared = 16, and z squared = 9, what is the greatest possible value of (x+y+z) squared?      Log On


   

Question 948643: If x squared = 25, y squared = 16, and z squared = 9, what is the greatest possible value of (x+y+z) squared?
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 = 25 ==> x = -5, 5
y^2 = 16 ==> y = -4, 4
z^2 = 0 ==> z = -3, 3

max((x+y+z)^2) = (3+4+5)^2 = 144