SOLUTION: There were 40 dimes and quarters in the drawer. Peggy counted them and found that their total value was $4.75. How many coins of each type were there?

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Question 948397: There were 40 dimes and quarters in the drawer. Peggy counted them and found that their total value was $4.75. How many coins of each type were there?
Found 2 solutions by josgarithmetic, stanbon:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
system%28d%2Bq=40%2C0.1d%2B0.25q=4.75%29

The money equation:
10d%2B25q=475
2d%2B5q=95

Simplified system of equations
system%28d%2Bq=40%2C2d%2B5q=95%29

Do the rest.

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
There were 40 dimes and quarters in the drawer. Peggy counted them and found that their total value was $4.75. How many coins of each type were there?
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Quantity:: d + q = 40 coins
Value::::10d+25q = 475 cents
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Modify::
2d + 2q = 80
2d + 5q = 95
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Subtract and solve for "q"::
3q = 15
q = 5 (# of quarters)
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Solve for "d"::
d = 40-5 = 35 (# of dimes)
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Cheers,
Stan H.
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