SOLUTION: Solve this equation on the interval 0 &#952; < 2&#960;. Round your answers to two decimal places. If there is no solution, enter NONE. cos(2&#952;) + 26 sin2 &#952; = 19

Algebra ->  Trigonometry-basics -> SOLUTION: Solve this equation on the interval 0 &#952; < 2&#960;. Round your answers to two decimal places. If there is no solution, enter NONE. cos(2&#952;) + 26 sin2 &#952; = 19       Log On


   

Question 948376: Solve this equation on the interval 0 θ < 2π. Round your answers to two decimal places. If there is no solution, enter NONE.
cos(2θ) + 26 sin2 θ = 19

(smallest value)

(largest value)
-There's four blank
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
Solve this equation on the interval 0 θ < 2π. Round your answers to two decimal places. If there is no solution, enter NONE.
cos(2θ) + 26 sin2 θ = 19
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1-2sin^2(t) + 26sin^2(t) = 19
24sin^2(t) = 18
sin^2(t) = 3/4
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sin(t) = sqrt(3)/2
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t = pi/3 or t = (2/3)pi
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Cheers,
Stan H.
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