Question 948221: 1. Mr. Alvarado is 20 years old older than his son. In 5 years, he will be 5 years more than twice as old as his son will then be. Find their present ages.
2. The sum of the ages of Sam and Tomas is 27 years. Seven years ago, Tomas was three years more than one-fourth as old as Sam. Find their present ages.
3. Rosa is twice as old as pilar. In four years, Rosa's age will be 2 years less than pilar's age 3 years ago. Find their present ages.
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! 1. Mr. Alvarado is 20 years old older than his son. In 5 years, he will be 5 years more than twice as old as his son will then be. Find their present ages.
f = s + 20
f+5 = 2s+5
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Substitute for "f"::
s+20+5 = 2s+5
s = 20 years (son's age now)
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2. The sum of the ages of Sam and Tomas is 27 years. Seven years ago, Tomas was three years more than one-fourth as old as Sam. Find their present ages.
s + t = 27
t-7 = (1/4)s + 3
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Substitute for "t" and solve for "s"::
27-s - 7 = (1/4)s + 3
20-s = (1/4)s + 3
(5/4)s = 17
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s = 68/5
s = 13 3/5 years (Sam's age now)
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Solve for "t"::
t = 20-s
t = 6 2/5 years (Tomas's age now)
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3. Rosa is twice as old as pilar. In four years, Rosa's age will be 2 years less than pilar's age 3 years ago. Find their present ages.
r = 2p
r+4 = p-3-2
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Substitute for "r" and solve for "p"::
2p+4 = p - 5
p = -9
Note: Pilar's age cannot be negative.
Please check your problem statement.
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Cheers,
Stan H.
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