SOLUTION: Write the first trigonometric function in terms of the second for θ in the given quadrant.
sec θ, sin θ; θ in Quadrant III
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sec θ, sin θ; θ in Quadrant III
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Question 948014: Write the first trigonometric function in terms of the second for θ in the given quadrant.
sec θ, sin θ; θ in Quadrant III Answer by lwsshak3(11628) (Show Source):
You can put this solution on YOUR website! Write the first trigonometric function in terms of the second for θ in the given quadrant.
sec θ, sin θ; θ in Quadrant III
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cos θ=-√(1-sin^2( θ))=-1/sec θ (in quadrant III where cos<0)
sec θ=-1/√(1-sin^2( θ))