SOLUTION: for each planet in a solar system, its year is the time it takes the planet to revolve around the center star.the formula E= 0.2X^3/2 models the number of the earth days in a plane

Algebra ->  Functions -> SOLUTION: for each planet in a solar system, its year is the time it takes the planet to revolve around the center star.the formula E= 0.2X^3/2 models the number of the earth days in a plane      Log On


   

Question 947946: for each planet in a solar system, its year is the time it takes the planet to revolve around the center star.the formula E= 0.2X^3/2 models the number of the earth days in a planet's year,E, where x is the average distance of the planet from the center star,in millions of kilometers. there are approximately 88 Earth days in the year of the planet mercury.What is the average distance of mercury from the star? Round to the nearest million kilometers.clearly state your final answer in a complete sentence.
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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for each planet in a solar system, its year is the time it takes the planet to revolve around the center star.
the formula E= 0.2X^3/2 models the number of the earth days in a planet's year,E, where x is the average distance of the planet from the center star,in millions of kilometers.
there are approximately 88 Earth days in the year of the planet mercury.What is the average distance of mercury from the star?

.2x%5E%283%2F2%29 = 88; the exponents is 3/2
x%5E%283%2F2%29 = 88%2F.2
x%5E%283%2F2%29 = 440
log%28x%5E%283%2F2%29%29 = log(440)
log equiv of exponents, find the log of 440
%283%2F2%29%2Alog%28x%29 = 2.64345
log x = 2%2F3 * 2.64345
log x = 1.7623
x = 57.85 ~ 58 million km is the av distance between the sun and mercury