Question 947860: If the mean height of college males is 70 inches with a standard deviation of 3 inches, what percentage of college males would be between 6' and 6'4"? Assume a normal distribution.
Using the information in problem 1, what height would someone have to be in order to be in the 99th percentile?
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! If the mean height of college males is 70 inches with a standard deviation of 3 inches, what percentage of college males would be between 6' and 6'4"? Assume a normal distribution.
z(72) = (72-70)/3 = 2/3
z(76) = (76-70)/3 = 2
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P(72 < x < 76) = P(2/3 < z < 2) = 0.2297
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Using the information in problem 1, what height would someone have to be in order to be in the 99th percentile?
Find the z-value with a left tail of 0.99
invNorm(0.99) = 2.3264
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Find the corresponding height value
x = 2.3264*3+70 = 76.98 inches
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Cheers,
Stan H.
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