SOLUTION: find three consecutive even integers such that 3 times the sum of the last two even integers is 40 more than 5 times the first integer

Algebra ->  Problems-with-consecutive-odd-even-integers -> SOLUTION: find three consecutive even integers such that 3 times the sum of the last two even integers is 40 more than 5 times the first integer       Log On


   

Question 947854: find three consecutive even integers such that 3 times the sum of the last two even integers is 40 more than 5 times the first integer
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39618) About Me  (Show Source):
You can put this solution on YOUR website!
2n, 2n+2, 2n+4.

3%28%282n%2B2%29%2B%282n%2B4%29%29=40%2B5%282n%29

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

find three consecutive even integers such that 3 times the sum of the last two even integers is 40 more than 5 times the first integer
Let the smallest integer be S

Then others are: S + 2, and S + 4

We then have: 3(S + 2 + S + 4) = 5S + 40

3(2S + 6) = 5S + 40



Solve for S, the smallest integer

Add 2 to S, or the smallest integer to get the middle larger

Add 2 to the middle integer or 4 to the smallest integer to get the 3rd or largest integer