SOLUTION: Someone please help me with this. Determine the values of the variable for which the expression is defined as a real number. (Enter your answer using interval notation.) sqrt

Algebra ->  Inequalities -> SOLUTION: Someone please help me with this. Determine the values of the variable for which the expression is defined as a real number. (Enter your answer using interval notation.) sqrt      Log On


   



Question 947657: Someone please help me with this.
Determine the values of the variable for which the expression is defined as a real number. (Enter your answer using interval notation.)
sqrt7x^2 − 58x + 16


Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
If you mean sqrt%287x%5E2-58x%2B16%29=sqrt(7x^2-58x+16),
you were missing some crucial parentheses.
sqrt%287x%5E2-58x%2B16%29 is a real number when 7x%5E2-58x%2B16%3E=0 .
Otherwise, for example for x=1 ,
what's inside the square root is negative,
and the square root is not defined as a real number.

y=7x%5E2-58x%2B16is a quadratic function that graphs as a parabola.
You can try to find its zeros by using the quadratic formula.
It does have zeros, and they are rational numbers,
so factoring also works in this case.
7x%5E2-58x%2B16=%287x-2%29%28x-8%29 is zero at x=2%2F7 and at x=8 .
In between those numbers, 7x-2%3E0 and x-8%3C0 ,
so their product, 7x%5E2-58x%2B16=%287x-2%29%28x-8%29 , is negative,
and sqrt%287x%5E2-58x%2B16%29 is not defined as a real number.
For any other value of x ,
7x%5E2-58x%2B16=%287x-2%29%28x-8%29%3E=0 ,
and sqrt%287x%5E2-58x%2B16%29 is defined as a real number.
So the answer is %22%28%22-infinity%22%2C%222%2F7%22%5D+U+%5B%228%22%2C%22infinity%22%29%22 .