SOLUTION: I'M TRYING TO UNDERSTAND HOW THE DERIVATIVE OF X^1/4 WAS OBTAINED. USEING THE FORMAT: lim h--0 f(X+h) - f(X-h)/ X+h - X-h OR 2h LIM h--0 1/2h [(X+h)^1/4 - (X-h)^1/4 ]

Algebra ->  Exponents -> SOLUTION: I'M TRYING TO UNDERSTAND HOW THE DERIVATIVE OF X^1/4 WAS OBTAINED. USEING THE FORMAT: lim h--0 f(X+h) - f(X-h)/ X+h - X-h OR 2h LIM h--0 1/2h [(X+h)^1/4 - (X-h)^1/4 ]       Log On


   



Question 947655: I'M TRYING TO UNDERSTAND HOW THE DERIVATIVE OF X^1/4 WAS OBTAINED. USEING
THE FORMAT: lim h--0 f(X+h) - f(X-h)/ X+h - X-h OR 2h
LIM h--0 1/2h [(X+h)^1/4 - (X-h)^1/4 ]
THE ANSWER BY USING THE POWER RULE IS 1/4X^3/4 BUT I CAN'T FIGURE OUT THE MATH TO PROVE IT.
CONFUSED AND IN SEARCH OF CLARITY

Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
The difference quotient needs to be this format:
%28f%28x%2Bh%29-f%28x%29%29%2Fh

f%28x%2Bh%29=%28x%2Bh%29%5E%281%2F4%29
and
f%28x%29=x%5E%281%2F4%29

Forming the difference quotient:
%28%28x%2Bh%29%5E%281%2F4%29-x%5E%281%2F4%29%29%2Fh


and from here, there is an algebraic trick taught in College Algebra during the study of limits, but unsure about how to work with it at this moment. Maybe you can review that and finish. I leave this unfinished posting up anyhow.