SOLUTION: a car travelled 25km at an average speed of xkm\h.if its speed was increased by 5km\h it covers the distance 15minutes earlier what is the original speed of car?

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Question 947651: a car travelled 25km at an average speed of xkm\h.if its speed was increased by 5km\h it covers the distance 15minutes earlier what is the original speed of car?
Found 2 solutions by m_obaid6@live.com, MathTherapy:
Answer by m_obaid6@live.com(1) About Me  (Show Source):
You can put this solution on YOUR website!
total distance = 25KM
first speed =x
first time = t
second speed =x+5
second time =t-5
x*t=x+5*t-5
25/t=25/t-5
25*t-5=t*25
sorry it is too hard

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
a car travelled 25km at an average speed of xkm\h.if its speed was increased by 5km\h it covers the distance 15minutes earlier what is the original speed of car?

At least he/she was honest about his/her inability to solve this problem!!
With average speed being x, time taken to travel 25 km = 25%2Fx
Increasing speed by 5 km/h means that its speed becomes: x + 5
Time taken to cover distance at new speed of x + 5: 25%2F%28x+%2B+5%29
We then get: 25%2Fx+=+25%2F%28x+%2B+5%29+%2B+15%2F60, which becomes: 25%2Fx+=+25%2F%28x+%2B+5%29+%2B+1%2F4
25(4)(x + 5) = 25(4x) + x(x + 5) -------- Multiplying by LCD, 4x(x + 5)
100x+%2B+500+=+100x+%2B+x%5E2+%2B+5x
x%5E2+%2B+5x+%2B+100x+-+100x+-+500+=+0
x%5E2+%2B+5x+-+500+=+0
(x - 20)(x + 25) = 0
x, or original speed = highlight_green%2820%29 km/h OR x = - 25 (ignore)