SOLUTION: `Pls help out: {{{ x^(2/3) -5x^(1/3) ( ) 6=0}}}

Algebra ->  Exponents -> SOLUTION: `Pls help out: {{{ x^(2/3) -5x^(1/3) ( ) 6=0}}}      Log On


   



Question 947405: `Pls help out: +x%5E%282%2F3%29+-5x%5E%281%2F3%29+%28+%29+6=0
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39620) About Me  (Show Source):
You can put this solution on YOUR website!
What you tried to express failed to render.

Your pure text is:
x^(2/3) -5x^(1/3) ( ) 6=0

Try adjusting your equation and placement of grouping symbols, and then what you want can be more clearly read and understood.

Maybe you have something of quadratic form, as this?
x^(2/3)-5x^(1/3)=6

and you could first make a substitution like u=x^(1/3), and then u^2=x^(1/3)*x^(1/3)=x^(2/3)

allowing to say,
u^2-5u=6
...
...

Rewrite your equation clearly in plain text, and then better help will be possible.

Answer by MathTherapy(10553) About Me  (Show Source):
You can put this solution on YOUR website!
`Pls help out: +x%5E%282%2F3%29+-5x%5E%281%2F3%29+%28+%29+6=0
Duplicate. Already answered!! Problem # 947406.