SOLUTION: newspaper carrier $6.85 in change 3 more quarters than dimes but four times as many nickles as quarters . how many coins of each ? Dimes ? quarters ? nickles ?

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Question 947393: newspaper carrier $6.85 in change 3 more quarters than dimes but four times as many nickles as quarters . how many coins of each ? Dimes ? quarters ? nickles ?
Answer by josgarithmetic(39620) About Me  (Show Source):
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Change the problem to this:
A newspaper carrier has $6.85 in change. There are 3 more quarters than dimes but four times as many nickles as quarters . How many coins of each? Dimes? quarters? nickles?


n, d, q, count of the coins

system%280.05n%2B0.1d%2B0.25q=6.85%2Cq-d=3%2Cn%2Fq=4%29.
Work through that system.

Think carefully about the system for a couple of minutes. You may see a strategy:
Simplify the first, money count equation. The second and third equations both include the variable, q, so solve the second equation for d, the third equation for n, and substitute these into the simplified money count equation.