SOLUTION: Mrs. Jones buys a computer for $2,050. The printer costs 25% of the computer. What is the price of the computer? --- I know the cost is $1,640 but I don't know how to explain it to

Algebra ->  Percentages: Solvers, Trainers, Word Problems and pie charts -> SOLUTION: Mrs. Jones buys a computer for $2,050. The printer costs 25% of the computer. What is the price of the computer? --- I know the cost is $1,640 but I don't know how to explain it to      Log On


   



Question 947345: Mrs. Jones buys a computer for $2,050. The printer costs 25% of the computer. What is the price of the computer? --- I know the cost is $1,640 but I don't know how to explain it to my daughter...
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39621) About Me  (Show Source):
You can put this solution on YOUR website!
Maybe the description is wrong.

COMPUTER AND PRINTER, $2050.
PRINTER, 25% of the purchase cost of $2050: %2825%2F100%29%282050%29=%281%2F4%29%282050%29=%281%2F2%29%281025%29=512.5.
JUST the computer: ENTIREPURCHASE-PRINTER, 2050-512.5=1537.5


I cannot reproduce what you are expecting.

Recheck your problem description and question, very carefully. One of us is missing something very simple.

Answer by MathTherapy(10555) About Me  (Show Source):
You can put this solution on YOUR website!

Mrs. Jones buys a computer for $2,050. The printer costs 25% of the computer. What is the price of the computer? --- I know the cost is $1,640 but I don't know how to explain it to my daughter...

Based on what you stated, the price of the computer is $2,050. Look at it!!
Anyway, it appears that you intended to say that the computer AND printer were purchased for $2,050.
That makes more sense.
Based on the correct and more sensible statement, we determine the price of the computer, as follows:
Let cost of computer be C
Then cost of printer = 25% of the computer, or .25C
Then we get: C + .25C = 2,050
1.25C = 2,050
C, or cost of computer = 2050%2F1.25, or highlight_green%28%22%24%221640%29