SOLUTION: When renting a car for her trip, Janice has the option of paying $0.32 a mile plus putting $25 down(option A) or she can pay $0.40 a mile (option B). What is the least amount of mi

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Question 947254: When renting a car for her trip, Janice has the option of paying $0.32 a mile plus putting $25 down(option A) or she can pay $0.40 a mile (option B). What is the least amount of miles Janice can drive to make option A the cheaper option?
Please help . I tried 0.32+x=25 and I subtracted 0.32 from both sides and I got x=2.18
PLEASE HELP!!
Answer by macston(5194) About Me  (Show Source):
You can put this solution on YOUR website!
$0.32x+$25=$0.40x subtract $0.32x from each side
$25.00=$0.08x Divide each side by $0.08
312.5=x
Actually, it makes sense if you realize mathematically you are making up the $25 at a rate of the 8 cent a mile difference. At 8 cents a mile, it takes 312.5 miles to make $25, so that is the break even point. More mileage favors Option A.