SOLUTION: Use logarithms to solve the equation 9(1.09^2x+1)=15 the 2x+1 is in expotential form.......

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Question 947205: Use logarithms to solve the equation
9(1.09^2x+1)=15
the 2x+1 is in expotential form.......
Found 2 solutions by Fombitz, Alan3354:
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
9%281.09%5E%282x%2B1%29%29=15
1.09%5E%282x%2B1%29=15%2F9
1.09%5E%282x%2B1%29=5%2F3
2x%2B1=log%281.09%2C%285%2F3%29%29
2x=log%281.09%2C%285%2F3%29%29-1
x=%281%2F2%29%28log%281.09%2C%285%2F3%29%29-1%29
highlight_green%28x=%281%2F2%29%28log%28%285%2F3%29%29%2Flog%28%281.09%29%29%29-1%2F2%29
approximately,
x=2.46

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Use logarithms to solve the equation
9(1.09^2x+1)=15
the 2x+1 is in expotential form
If you mean it's an exponent:
================
9(1.09^2x+1)=15
1.09^(2x+1)= 5/3
(2x+1)*log(1.09) = log(5/3)
2x+1 = log(5/3)/log(1.09)
x = (-1 + log(5/3)/log(1.09))/2