SOLUTION: the length of a rectangle is 5 times longer than its width. If the diagonal of the rectangle measures 12 inches, what is its length? Type your answer as a decimal to the nearest hu

Algebra ->  Rectangles -> SOLUTION: the length of a rectangle is 5 times longer than its width. If the diagonal of the rectangle measures 12 inches, what is its length? Type your answer as a decimal to the nearest hu      Log On


   



Question 947099: the length of a rectangle is 5 times longer than its width. If the diagonal of the rectangle measures 12 inches, what is its length? Type your answer as a decimal to the nearest hundredth
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
: the length of a rectangle is 5 times longer than its width.
If the diagonal of the rectangle measures 12 inches, what is its length?
:
Let x = the width of the rectangle
the length is five times the width, therefore:
5x = the length
Using pythag; a^2 + b^2 = c^2
a = x
b = 5x
c = 12
x^2 + (5x)^2 = 12^2
x^2 + 25x^2 = 144
26x^2 = 144
x^2 = 144/26
x^2 = 5.538
x = sqrt%285.538%29
x = 2.353 inches is the width
then
5(2.353) = 11.767 is the length
" Type your answer as a decimal to the nearest hundredth"
11.77 by 2.35 inches
:
:
Check this on your calc enter sqrt%2811.77%5E2%2B2.35%5E2%29