SOLUTION: I'm very confused about the general form equation. Ax+By+C=0 Where do the A, B and C come from?? I'm supposed to translate the point (-3, 5) with a slope of 1/4 into the genera

Algebra ->  Linear-equations -> SOLUTION: I'm very confused about the general form equation. Ax+By+C=0 Where do the A, B and C come from?? I'm supposed to translate the point (-3, 5) with a slope of 1/4 into the genera      Log On


   



Question 94703: I'm very confused about the general form equation. Ax+By+C=0
Where do the A, B and C come from??
I'm supposed to translate the point (-3, 5) with a slope of 1/4 into the general form of a line.
I plugged this information into the point-slope formula and got y=1/4x-3/2 but that's not in the general form.
I tried to just switch formulas by rearranging the slope-intercept formula and got 4x-y-3/2=0.
I guess I really need to know how to create a general form equation and how to switch between slope-intercept and general forms.
Thank you =]

Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
I'm supposed to translate the point (-3, 5) with a slope of 1/4 into the general form of a line.
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Using the slope-intercept form you know m=1/4 and y=5 when x=-3.
5 = (1/4)(-3)=b
5 = (-3/4) + b
b = 5+3/4
b = 23/4
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EQUATION:
y = (1/4)x+23/4
Now put that into the standard form:
Multiply thru by 4 to get:
4y = x + 23
x-4y+23 = 0 is the standard form.
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Cheers,
Stan H.

Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
point (-3, 5) with a slope of 1/4
y-y%5B1%5D=m%28x-x%5B1%5D%29 (Point-slope form)
y-5=.25(x-(-3))
y-5=.25(x+3)
y-5=.25x+.75
add 5 to both sides. y=.25x+5.75 (Slope-intercept form) y=mx+b
subtract y from both sides. .25x-y+5.75=0 (General form) Ax+By+C=0
I can see you're working hard. Keep it up. It took me a long time to get it.
Ed Jones
graph%28500%2C500%2C-10%2C10%2C-10%2C10%2C.25x%2B5.75%29