SOLUTION: the smallest of three consecutive integers is 18 less than the sum of the two larger intergers find the three integers
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Question 946757
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the smallest of three consecutive integers is 18 less than the sum of the two larger intergers find the three integers
Answer by
CubeyThePenguin(3113)
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integers: (x-1), x, (x+1)
x - 1 = (x + (x+1)) - 18
x - 1 = 2x - 17
16 = x
The integers are 15, 16, and 17.