SOLUTION: When the shot whose path is released at an angle of 65�, its height, g(x), in feet, can be modeled by: g(x) = �0.04x2 + 2.1x + 6.1 where x is the shot�s horizontal distance, in fee

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Question 946580: When the shot whose path is released at an angle of 65�, its height, g(x), in feet, can be modeled by: g(x) = �0.04x2 + 2.1x + 6.1 where x is the shot�s horizontal distance, in feet, from its point of release. Use this model to solve the following: (a) What is the maximum height, to the nearest tenth of a foot, of the shot and how far from its point of release does this occur? (b) What is the shot�s maximum horizontal distance, to the nearest tenth of a foot, or the distance of the throw? (c) from what height was the shot released?
Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website!

This is in the form:
where

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(a)
The component of the maximum
height is :

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To the nearest 10th, the maximum height
is 33.7 ft
The maximum height is reached 26.25 ft
from the point of release
-----------------------
(b)

Use the quadratic formula

The maximum horizontal distance is:
55.3 ft to the nearest tenth
-------------------------
(c)
To find height from which shot is released, se the
horizontal distance, to

The shot was released from a height of 6.1 ft
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Here's a plot: