SOLUTION: A freight train left Bangalore and traveled south. One hour later a passenger train left traveling 20 km/h faster in an effort to catch up to it. After three hours the passenger

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Question 946314: A freight train left Bangalore and traveled south. One hour later a passenger train left traveling 20 km/h faster in an effort to catch up to it. After three hours the passenger train finally caught up. Find the freight train's average speed.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A freight train left Bangalore and traveled south. One hour later a passenger train left traveling 20 km/h faster in an effort to catch up to it. After three hours the passenger train finally caught up. Find the freight train's average speed.
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Passenger train DATA::
time = 3 hrs ; rate = x+20 km/hr ; distance = r*t = 3(x+20) km
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Freight train DATA:
time = 4 hrs ; rate = x km/hr ; distance = r*t = 4x km
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Equation:
distance = distance
4x = 3x+60
x = 60 km/hr (freight train rate)
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Cheers,
Stan H.
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