Question 946224: Hello! I was asked this question: "The general equation of a plane is Ax + By + Cz = D, where A, B, C, and D are real numbers and A is nonnegative. Find the equation of the plane containing the points (3, 0, 0), (0, 6, 0), and (0, 0, 6). Show each step of your process." I am not quite sure on how to complete this question. If you could walk me through this, that would be great. Thanks
Answer by Fombitz(32388)   (Show Source):
You can put this solution on YOUR website! Let P=(3,0,0), Q=(0,6,0), and R=(0,0,6).
Find PQ and PR, two vectors that lie in the plane.
PQ=(-3,6,0)
PR=(-3,0,6)
Now find the cross product to have a vector normal to the plane.
PQ X PR= (36,18,18)=(2,1,1)
So the plane has the form,
Now use any point to solve for D.
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